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Repairable Systems Analysis Reference Example |
This example compares the results for a repairable systems analysis.
Reference Case
Crow, L.H., Reliability Analysis for Complex Repairable Systems, Reliability and Biometry: Statistical Analysis of Lifelength, pg. 385, 1974.
Data
| System 1 | System 2 | System 3 |
|---|---|---|
| 4.3 | 0.1 | 8.4 |
| 4.4 | 5.6 | 32.4 |
| 10.2 | 18.6 | 44.7 |
| 23.5 | 19.5 | 48.4 |
| 23.8 | 24.2 | 50.6 |
| 26.4 | 26.7 | 73.6 |
| 74 | 45.1 | 98.7 |
| 77.1 | 45.8 | 112.2 |
| 92.1 | 72.7 | 129.8 |
| 197.2 | 75.7 | 136 |
| 98.6 | 195.8 | |
| 120.1 | ||
| 161.8 | ||
| 180.6 | ||
| 190.8 |
Result
Beta = 0.615, Lambda = 0.461
Results in Weibull++
Since [math]\displaystyle{ \,\!S_{1}=S_{2}=S_{3}=0 }[/math] and [math]\displaystyle{ \,\!T_{1}=T_{2}=T_{3}=200 }[/math] then the maximum likelihood estimates of [math]\displaystyle{ \,\!\hat{\beta} }[/math] and [math]\displaystyle{ \,\!\hat{\lambda } }[/math] are given by:
[math]\displaystyle{ \,\!\hat{\beta }=\sum_{q=1}^{K}N_{q} }[/math]