Repository.Xfmea.GetAllXfmeaFailuresDictionary Method: Difference between revisions
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'''VB.NET''' | '''VB.NET''' | ||
{{APIComment|' | {{APIComment|'Declare a new Repository object and connect to a Synthesis repository.}} | ||
{{APIPrefix|Dim}} MyRepository {{APIPrefix|As New}} Repository | {{APIPrefix|Dim}} MyRepository {{APIPrefix|As New}} Repository | ||
MyRepository.ConnectToAccessRepository({{APIString|"C:\RSRepository1.rsr10"}}) | |||
{{APIComment|'Open project #1 and get a dictionary of all failures associated with FMEA function #1.}} | {{APIComment|'Open project #1 and get a dictionary of all failures associated with FMEA function #1.}} | ||
{{APIPrefix|Dim}} Dict {{APIPrefix|As}} Dictionary (of Integer, XfmeaFailure) | |||
MyRepository.Project.SetCurrentProject(1) | |||
Dict = MyRepository.Xfmea.GetAllXfmeaFailuresDictionary(1) | |||
{{APIComment|'Output sample: Display the number of entries in the dictionary.}} | {{APIComment|'Output sample: Display the number of entries in the dictionary.}} | ||
MsgBox(Dict.Count) |
Revision as of 18:06, 8 April 2016
Member of: SynthesisAPI.Repository
Gets a dictionary of the failures associated with an FMEA function. Returns a Dictionary(Of Integer, XfmeaFailure) object, where the keys are the ID numbers of the failures. (VB.NET only)
Syntax
.Xfmea.GetAllXfmeaFailuresDictionary(FunctionID)
Parameters
FunctionID
- Required. Integer. The record ID of the FMEA function.
Example
This example assumes that system hierarchy items with FMEAs exists in the first available project of a repository.
VB.NET 'Declare a new Repository object and connect to a Synthesis repository. Dim MyRepository As New Repository MyRepository.ConnectToAccessRepository("C:\RSRepository1.rsr10") 'Open project #1 and get a dictionary of all failures associated with FMEA function #1. Dim Dict As Dictionary (of Integer, XfmeaFailure) MyRepository.Project.SetCurrentProject(1) Dict = MyRepository.Xfmea.GetAllXfmeaFailuresDictionary(1) 'Output sample: Display the number of entries in the dictionary. MsgBox(Dict.Count)