# Logistic Distribution Example

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[math]\overset{{}}{\mathop{\text{Times-to-Failure Data with Suspensions}}}\,\,\![/math]
[math]\begin{matrix}
\text{Data Point Index} & \text{State F or S} & \text{State End Time} \\
\text{1} & \text{F} & \text{8} \\
\text{2} & \text{F} & \text{10} \\
\text{3} & \text{F} & \text{15} \\
\text{4} & \text{F} & \text{17} \\
\text{5} & \text{F} & \text{19} \\
\text{6} & \text{F} & \text{26} \\
\text{7} & \text{F} & \text{27} \\
\text{8} & \text{S} & \text{28} \\
\text{9} & \text{S} & \text{28} \\
\text{10} & \text{S} & \text{28} \\
\end{matrix}\,\![/math]

*This example appears in the Life Data Analysis Reference book*.

The lifetime of a mechanical valve is known to follow a logistic distribution. 10 units were tested for 28 months and the following months-to-failure data were collected.

- Determine the valve's design life if specifications call for a reliability goal of 0.90.
- The valve is to be used in a pumping device that requires 1 month of continuous operation. What is the probability of the pump failing due to the valve?

Enter the data set in a Weibull++ standard folio, as follows:

The computed parameters for maximum likelihood are:

- [math]\begin{align} & \widehat{\mu }= & 22.34 \\ & \hat{\sigma }= & 6.15 \end{align}\,\![/math]

The valve's design life, along with 90% two sided confidence bounds, can be obtained using the QCP as follows:

The probability, along with 90% two sided confidence bounds, that the pump fails due to a valve failure during the first month is obtained as follows: