Repository.Model.AddModel

Member of: SynthesisAPI.Repository

Adds a new model resource to the current project. Returns a Boolean value; when true, indicates a successful save.

If a model with the same name already exists in the destination project, the name will be incremented automatically. For example, if "Model1" already exists, the new model might be renamed to "Model2," "Model3," etc.

Syntax

.Model.AddModel(m)

Parameters

m

Required. The cModel object that represents the model resource to be added.

Example

This example creates a new model resource, and then saves it in the first available project in a Synthesis repository.

VBA

 'Declare a new Repository object and connect to a Synthesis repository. 
  Dim MyRepository As New Repository
  MyRepository.ConnectToAccessRepository("C:\RSRepository1.rsr10")
 
 'Create a new model. The following example creates a 2-parameter Weibull reliability model, 
 'with beta = 1 and eta = 100. The model name is "MyNewModel." 
  Dim ModelType As ModelTypeEnum
  Dim ModelCategory As ModelCategoryEnum
  Dim ModelName As String
  Dim ModelParams(2) As Double
 
  ModelType = ModelTypeEnum_Weibull2
  ModelCategory = ModelCategoryEnum_Reliability
  ModelName = "MyNewModel"
  ModelParams(0) = 1
  ModelParams(1) = 100

  Dim newModel As New cModel
  Call newModel.SetModel(ModelType, ModelCategory, ModelName, ModelParams)

 'Add the new model to project #1. 
  MyRepository.Project.SetCurrentProject(1)   
  Call MyRepository.Model.AddModel(newModel)

VB.NET

 'Declare a new Repository object and connect to a Synthesis repository. 
  Dim MyRepository As New Repository
  MyRepository.ConnectToAccessRepository("C:\RSRepository1.rsr10")
 
 'Create a new model. The following example creates a 2-parameter Weibull reliability model, 
 'with beta = 1 and eta = 100. The model name is "MyNewModel." 
  Dim newModel As New cModel(ModelTypeEnum.Weibull2, ModelCategoryEnum.Reliability, "MyNewModel", 1, 100)

 'Add the new model to project #1. 
  MyRepository.Project.SetCurrentProject(1)   
  MyRepository.Model.AddModel(newModel)