Redundant Systems RBD

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Redundant Systems RBD

This example validates the results for redundant systems in BlockSim's analytical and simulation diagrams.


Reference Case

The data set is from example 4.7 on page 81 in the book Life Cycle Reliability Engineering by Dr. Guangbin Yang, John Wiley & Sons, 2007.


Data

A small power plant is equipped with two identical generators in a cold standby system configuration. Hence, the standby generator starts working as soon as the active generator fails. The assumptions are that there are no interruptions between switches and that the switching system is 100% reliable. Each generator follows an exponential life distribution with a failure rate (lambda) of 3.6 × 10-5 failures per hour. The reliability of the power plant at 5000 hours and the mean time to failure (MMTF) is calculated.


Result

Substituting the lambda and time into Equation 4.31 on page 81, the reliability of the system is calculated as 98.56% at time 5000 hours.

[math]\displaystyle{ R(t) = (1 + \lambda t)e^{-\lambda t} \,\! }[/math]
[math]\displaystyle{ R(5000) = (1 + (3.6 \times 10^{-5}) \times 5000)e^{-(3.6 \times 10^{-5}) \times 5000} = 0.9856\,\! }[/math]


By setting n = 2 in Equation 4.3 on page 81, the mean time to failure is calculated as 5.56 x 104 hours.

[math]\displaystyle{ MTTF = \frac{n}{\lambda}=\frac{2}{3.6 \times 10^{-5}}= 5.56 \times 10^{4} \,\! }[/math]


Results in BlockSim