Normal Distribution with MLE Solution: Difference between revisions

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Failure times of components are: 14, 18, 18, 20, 21, 22, 22, 20, 17, 17, 15, 13.  
The failure times of the components are: 14, 18, 18, 20, 21, 22, 22, 20, 17, 17, 15, 13.  




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The following picture shows the results in Weibull++.


[[Image:Normal_parameters.png|center]]
[[Image:Normal_parameters.png|center]]

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Normal Distribution with MLE Solution

This example compares the variance and covariance matrix for a Normal distribution with ML estimates.


Reference Case

The data set is from Example 4.17 on page 246 in the book Reliability Engineering by Dr. Elsayed, Addison Wesley Longman, Inc, 1996.


Data

The failure times of the components are: 14, 18, 18, 20, 21, 22, 22, 20, 17, 17, 15, 13.


Result

[math]\displaystyle{ \Gamma ^{1} = \begin{bmatrix} 0.700 & 0\\ 0 & 0.350 \end{bmatrix}\,\! }[/math]


Results in Weibull++

The following picture shows the results in Weibull++.

Normal parameters.png
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