Median Rank for Multiple Censored Data: Difference between revisions
Kate Racaza (talk | contribs) (Created page with '{{UConstruction}}{{Banner Weibull Reference Examples}}__NOTOC__ This example validates the median rank calculation for multiple censored data. =Data Source= Table 3.1 on page 78 …') |
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=Results from Weibull++ | =Results from Weibull++= | ||
The coordinates of each point in the following plot shows the failure time and the corresponding median rank. | The coordinates of each point in the following plot shows the failure time and the corresponding median rank. | ||
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The differences between the results in Weibull++ and the book are due to the method of calculating the median ranks (MR). In the book, the following approximation method is used. | The differences between the results in Weibull++ and the book are due to the method of calculating the median ranks (MR). In the book, the following approximation method is used. | ||
::<math>MR_{i}\approx \frac{MON_{i}-0.3}{N+0.4}</math> | |||
<math>MR_{i}\approx \frac{MON_{i}-0.3}{N+0.4}</math> | |||
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In Weibull++, the following exact method is used. | In Weibull++, the following exact method is used. | ||
::<math>MR_{i}= \frac{1}{1+\frac{N-MON_{i}+1}{MON_{i}}F_{0.5,m,n}}</math> | |||
<math>MR_{i}= \frac{1}{1+\frac{N-MON_{i}+1}{MON_{i}}F_{0.5,m,n}}</math> | |||
where <math>m=2(N-MON_{i}+1), n=2xMON_{i}\cdot F_{0.5,m,n}\,\!</math> is the 50 percentile of a F distribution with degree of freedom of ''m'' and ''n''. | where <math>m=2(N-MON_{i}+1), n=2xMON_{i}\cdot F_{0.5,m,n}\,\!</math> is the 50 percentile of a F distribution with degree of freedom of ''m'' and ''n''. | ||
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This example validates the median rank calculation for multiple censored data.
Data Source
Table 3.1 on page 78 in book “Reliability & Life Testing Handbook Vol 2” by Dr. Kececioglu, Prentice-Hall, 1994.
Data
| Num. In Stage | State F or S | Time to Failure |
|---|---|---|
| 1 | F | 5100 |
| 1 | S | 9500 |
| 1 | F | 15000 |
| 1 | S | 22000 |
| 1 | F | 40000 |
Result
| Num. In Stage | State F or S | Time to Failure | Median Rank (%) |
|---|---|---|---|
| 1 | F | 5100 | 12.94 |
| 1 | S | 9500 | |
| 1 | F | 15000 | 36.1 |
| 1 | S | 22000 | |
| 1 | F | 40000 | 70.84 |
Results from Weibull++
The coordinates of each point in the following plot shows the failure time and the corresponding median rank.
The differences between the results in Weibull++ and the book are due to the method of calculating the median ranks (MR). In the book, the following approximation method is used.
- [math]\displaystyle{ MR_{i}\approx \frac{MON_{i}-0.3}{N+0.4} }[/math]
where [math]\displaystyle{ MR_{i}\,\! }[/math] is the median rank at the [math]\displaystyle{ ith\,\! }[/math] failure time; [math]\displaystyle{ MON_{i}\,\! }[/math] is the mean order number; [math]\displaystyle{ N\,\! }[/math] is the total samples. For the step by step calculation of mean order number (MON), please refer to the book “Reliability & Life Testing Handbook Vol 2” by Dr. Kececioglu, Prentice-Hall, 1994.
In Weibull++, the following exact method is used.
- [math]\displaystyle{ MR_{i}= \frac{1}{1+\frac{N-MON_{i}+1}{MON_{i}}F_{0.5,m,n}} }[/math]
where [math]\displaystyle{ m=2(N-MON_{i}+1), n=2xMON_{i}\cdot F_{0.5,m,n}\,\! }[/math] is the 50 percentile of a F distribution with degree of freedom of m and n.