Expected Failure Time Plot: Difference between revisions

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Furthermore, consider that for the units to be tested the underlying reliability model assumption is given by a Weibull distribution with <span class="texhtml">β = 2</span>, and <span class="texhtml">η = 100</span> hr.  
Furthermore, consider that for the units to be tested the underlying reliability model assumption is given by a Weibull distribution with <math>\beta = 2</math>, and <math>\eta = 100</math> hr.  


Then the median time to failure of the first unit on test can be determined by solving the Weibull reliability equation for t, at each probability,  
Then the median time to failure of the first unit on test can be determined by solving the Weibull reliability equation for t, at each probability,  

Revision as of 18:17, 2 March 2011

UNDER CONSTRUCTION
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Expected Failure Time Plot

When a reliability life test is planned it is useful to visualize the expected outcome of the experiment. The Expected Failure Time Plot (introduced by ReliaSoft in Weibull++ 8)provides such visual.

Background & Calculations

Using the cumulative binomial, for a defined sample size, one can compute a rank (Median Rank if at 50% probability) for each ordered failure. As an example and for a sample size of 6 the 5%, 50% and 95% ranks would be as follows:


Table 1: 5%, 50% and 95% Ranks for a sample size of 6. 
Order Number 5% 50% 95%
1 0.85% 10.91% 39.30%
2 6.29% 26.45% 58.18%
3 15.32% 42.14% 72.87%
4 27.13% 57.86% 84.68%
5 41.82% 73.55% 93.71%
6 60.70%

89.09%

99.15%


Furthermore, consider that for the units to be tested the underlying reliability model assumption is given by a Weibull distribution with [math]\displaystyle{ \beta = 2 }[/math], and [math]\displaystyle{ \eta = 100 }[/math] hr.

Then the median time to failure of the first unit on test can be determined by solving the Weibull reliability equation for t, at each probability,

or

[math]\displaystyle{ R(t)=e^{\big({t \over \eta}\big)^\beta} }[/math]

then for 0.85%,


[math]\displaystyle{ 1-0.0085=e^{\big({t \over 100}\big)^2} }[/math]

and so forths as shown in the table below:


Failure Order Number Lowest Expected Time-to-failure (hr) Median Expected Time-to-failure (hr) Highest Expected Time-to-failure (hr)
1 9.25 33.99 70.66
2 25.48 55.42 93.37
3 40.77 73.97 114.21
4 56.26 92.96 136.98
5 73.60 115.33 166.34
6

96.64

148.84 218.32