Repository.Pool.GetPool: Difference between revisions
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Alex Ulanov (talk | contribs) |
Alex Ulanov (talk | contribs) |
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Success = MyRepository.ConnectToRepository("RepositoryFileNamePath") | Success = MyRepository.ConnectToRepository("RepositoryFileNamePath") | ||
{{APIComment|' | {{APIComment|'Set a first available project as current.}} | ||
MyRepository.Project.SetCurrentProject(0) | |||
{{APIComment|'Get a Pool with the ID of 1.}} | |||
{{APIComment|'Get a Pool.}} | |||
Dim GetPool() as cPool | Dim GetPool() as cPool | ||
GetPool= MyRepository.Pool.GetPool(1) | GetPool= MyRepository.Pool.GetPool(1) |
Revision as of 20:52, 22 May 2015
Version 10 Only - Returns pool with the provided ID. Returns nothing if the pool doesn't exist.
Syntax
- GetPool(As cPool)
Parameters
Enter the Pool ID to get desired pool.
Usage Example
'Declare a new repository connection object. Dim MyRepository As New Repository 'Connect to the Synthesis repository. Dim Success As Boolean = False Success = MyRepository.ConnectToRepository("RepositoryFileNamePath") 'Set a first available project as current. MyRepository.Project.SetCurrentProject(0) 'Get a Pool with the ID of 1. Dim GetPool() as cPool GetPool= MyRepository.Pool.GetPool(1)