Inverse Power Law Example: Difference between revisions
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The data set was analyzed jointly in an ALTA standard folio using the IPL-Weibull model, with a complete MLE solution over the entire data set. The analysis yields: | The data set was analyzed jointly in an ALTA standard folio using the IPL-Weibull model, with a complete MLE solution over the entire data set. The analysis yields: | ||
::<math>\widehat{\beta }=2.616464</math> | ::<math>\widehat{\beta }=2.616464\,\!</math> | ||
::<math>\widehat{K}=0.001022</math> | ::<math>\widehat{K}=0.001022\,\!</math> | ||
::<math>\widehat{n}=1.327292</math> | ::<math>\widehat{n}=1.327292\,\!</math> |
Revision as of 21:48, 21 September 2012
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This example appears in the Accelerated Life Testing Data Analysis Reference book.
Consider the following times-to-failure data at two different stress levels.
The data set was analyzed jointly in an ALTA standard folio using the IPL-Weibull model, with a complete MLE solution over the entire data set. The analysis yields:
- [math]\displaystyle{ \widehat{\beta }=2.616464\,\! }[/math]
- [math]\displaystyle{ \widehat{K}=0.001022\,\! }[/math]
- [math]\displaystyle{ \widehat{n}=1.327292\,\! }[/math]