Repository.Project.GetCurrentProject: Difference between revisions
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<onlyinclude>Returns a '''[[NameIdPair Class|NameIDPair]]''' object that | <onlyinclude>Returns a '''[[NameIdPair Class|NameIDPair]]''' object that represents the name and ID pair of the current project.</onlyinclude> | ||
== Syntax == | == Syntax == | ||
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'''VBA|VB.NET''' | '''VBA|VB.NET''' | ||
{{APIComment|' | {{APIComment|'Declare a new Repository object and connect to a Synthesis repository.}} | ||
{{APIPrefix|Dim}} MyRepository {{APIPrefix|As New}} Repository | {{APIPrefix|Dim}} MyRepository {{APIPrefix|As New}} Repository | ||
MyRepository.ConnectToAccessRepository({{APIString|"C:\RSRepository1.rsr10"}}) | |||
{{APIComment|'Set the first available project in the repository as the current project.}} | {{APIComment|'Set the first available project in the repository as the current project.}} | ||
Latest revision as of 17:30, 9 June 2016
 |
Member of: SynthesisAPI.Repository
Returns a NameIDPair object that represents the name and ID pair of the current project.
Syntax
.Project.GetCurrentProject
Example
VBA|VB.NET 'Declare a new Repository object and connect to a Synthesis repository. Dim MyRepository As New Repository MyRepository.ConnectToAccessRepository("C:\RSRepository1.rsr10") 'Set the first available project in the repository as the current project. MyRepository.Project.SetCurrentProject(1) 'Output example: Display the name and ID of the current project. Dim ProjectName As String Dim ProjectID As Integer ProjectName = MyRepository.Project.GetCurrentProject.Name ProjectID = MyRepository.Project.GetCurrentProject.ID MsgBox ("You are currently connected to: " & ProjectName & ", ID#" & ProjectID)