Arrhenius-Lognormal Model for Interval Data: Difference between revisions
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{{Reference Example| | {{Reference Example|{{Banner ALTA Reference Examples}}}} | ||
This example | This example validates the results for the Arrhenius-lognormal model with interval data in ALTA standard folios. | ||
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{{Reference_Example_Heading2}} | {{Reference_Example_Heading2}} | ||
The data set for a new-technology IC | The data set for a new-technology IC device is given below. | ||
{| {{table}} | {| {{table}} | ||
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The above equation is the general log-linear model in ALTA. In ALTA, the coefficients are denoted by <math>\alpha_{i}\,\!</math>. We can see <math>\beta_{0} = \alpha_{0}\,\!</math> and <math>\beta_{1} = \frac{\alpha_{1}}{11605}\,\!</math>. | The above equation is the general log-linear model in ALTA. In ALTA, the coefficients are denoted by <math>\alpha_{i}\,\!</math>. We can see that <math>\beta_{0} = \alpha_{0}\,\!</math> and <math>\beta_{1} = \frac{\alpha_{1}}{11605}\,\!</math>. | ||
In fact, the above model can also be expressed using the traditional Arrhenius model: | In fact, the above model can also be expressed using the traditional Arrhenius model: | ||
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In the book, the following results are provided: | In the book, the following results are provided: | ||
* ML estimations for the model parameters are: <math>\sigma\,\!</math> = 0.52, <math>\beta_{0}\,\!</math> = -10.2, <math>\beta_{1}\,\!</math> = 0.83, (<math>\alpha_{1}\,\!</math> = <math>\beta_{1}\times \,\!</math> 11605 = 9632.15). | * The ML estimations for the model parameters are: <math>\sigma\,\!</math> = 0.52, <math>\beta_{0}\,\!</math> = -10.2, <math>\beta_{1}\,\!</math> = 0.83, (<math>\alpha_{1}\,\!</math> = <math>\beta_{1}\times \,\!</math> 11605 = 9632.15). | ||
* The standard deviation of each parameter: <math>std(\sigma)\,\!</math> = 0.06, <math>std(\beta_{0})\,\!</math> = 1.5, <math>std(\beta_{1})\,\!</math> = 0.07. Therefore, their variances are: <math>Var(\sigma)\,\!</math> = 0.0036, <math>Var(\beta_{0})\,\!</math> = 2.25, <math>Var(\beta_{1})\,\!</math> = 0.0049. In terms of <math>\alpha_{1}\,\!</math> , the variance is <math>Var(\alpha_{1})\,\!</math> = 11605<sup>2</sup> and <math>Var(\beta_{1})\,\!</math> = 659912.5. | * The standard deviation of each parameter: <math>std(\sigma)\,\!</math> = 0.06, <math>std(\beta_{0})\,\!</math> = 1.5, <math>std(\beta_{1})\,\!</math> = 0.07. Therefore, their variances are: <math>Var(\sigma)\,\!</math> = 0.0036, <math>Var(\beta_{0})\,\!</math> = 2.25, <math>Var(\beta_{1})\,\!</math> = 0.0049. In terms of <math>\alpha_{1}\,\!</math> , the variance is <math>Var(\alpha_{1})\,\!</math> = 11605<sup>2</sup> and <math>Var(\beta_{1})\,\!</math> = 659912.5. | ||
* The 95% two-sided confidence bounds are: for <math>\sigma\,\!</math> it is [0.42, 0.64]; for <math>\beta_{0}\,\!</math> it is [-13.2, -7.2]; for <math>\beta_{1}\,\!</math> it is [0.68, 0.97]. In terms of <math>\alpha_{1}\,\!</math>, the bounds are [7891.14, 11256.85]. | * The 95% two-sided confidence bounds are: for <math>\sigma\,\!</math> it is [0.42, 0.64]; for <math>\beta_{0}\,\!</math> it is [-13.2, -7.2]; for <math>\beta_{1}\,\!</math> it is [0.68, 0.97]. In terms of <math>\alpha_{1}\,\!</math>, the bounds are [7891.14, 11256.85]. | ||
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The picture above also shows | The picture above also shows variance of each parameter. These are: <math>Var(\sigma)\,\!</math> = 0.003303, <math>Var(\alpha_{0})\,\!</math> = 2.331652, <math>Var(\alpha_{1})\,\!</math> = 721392.210588. In terms of <math>\beta_{1}\,\!</math> , the variance is <math>Var(\beta_{1}) = \frac{Var(\alpha_{1})}{11605^{2}}\,\!</math> = 0.0053565. | ||
The differences in the variance in ALTA and the results in the book are caused by the precision in the book since results are provided only up to the 2nd decimal. | The differences in the variance in ALTA and the results in the book are caused by the precision in the book since results are provided only up to the 2nd decimal. |
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