Logistic Confidence Bounds Example: Difference between revisions
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<noinclude>{{Banner RGA Examples}} | <noinclude>{{Banner RGA Examples}} | ||
''This example appears in the [ | ''This example appears in the [https://help.reliasoft.com/reference/reliability_growth_and_repairable_system_analysis Reliability growth reference]''. | ||
</noinclude> | </noinclude> | ||
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#The parameters <math>b\,\!</math> and <math>k\,\!</math>. | #The parameters <math>b\,\!</math> and <math>k\,\!</math>. | ||
#Reliability at month 5. | #Reliability at month 5. | ||
'''Solution''' | '''Solution''' | ||
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<li>The values of <math>\hat{b}\,\!</math> and <math>\hat{k}\,\!</math> that were estimated from the least squares analysis in the reliability data example are: | <li>The values of <math>\hat{b}\,\!</math> and <math>\hat{k}\,\!</math> that were estimated from the least squares analysis in the reliability data example are: | ||
:<math>\begin{align} | |||
\widehat{b}= & 3.3991 \\ | \widehat{b}= & 3.3991 \\ | ||
\widehat{\alpha }= & 0.7398 | \widehat{\alpha }= & 0.7398 | ||
\end{align}\,\!</math> | \end{align}\,\!</math> | ||
Thus, the 2-sided 90% confidence bounds on parameter <math>b\,\!</math> are: | |||
:<math>\begin{align} | |||
{{b}_{lower}}= & 2.5547 \\ | {{b}_{lower}}= & 2.5547 \\ | ||
{{b}_{upper}}= & 4.5225 | {{b}_{upper}}= & 4.5225 | ||
\end{align}\,\!</math> | \end{align}\,\!</math> | ||
The 2-sided 90% confidence bounds on parameter <math>k\,\!</math> are: | |||
:<math>\begin{align} | |||
{{k}_{lower}}= & 0.6798 \\ | {{k}_{lower}}= & 0.6798 \\ | ||
{{k}_{upper}}= & 0.7997 | {{k}_{upper}}= & 0.7997 | ||
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<li>First, calculate the reliability estimation at month 5: | <li>First, calculate the reliability estimation at month 5: | ||
:<math>\begin{align} | |||
{{R}_{5}}= & \frac{1}{1+b{{e}^{-5k}}} \\ | {{R}_{5}}= & \frac{1}{1+b{{e}^{-5k}}} \\ | ||
= & 0.9224 | = & 0.9224 | ||
\end{align}\,\!</math> | \end{align}\,\!</math> | ||
Thus, the 2-sided 90% confidence bounds on reliability at month 5 are: | |||
::<math>\begin{align} | ::<math>\begin{align} | ||
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{{[{{R}_{5}}]}_{upper}}= & 0.9955 | {{[{{R}_{5}}]}_{upper}}= & 0.9955 | ||
\end{align}\,\!</math> | \end{align}\,\!</math> | ||
The next figure shows a graph of the reliability plotted with 2-sided 90% confidence bounds. | The next figure shows a graph of the reliability plotted with 2-sided 90% confidence bounds. | ||
[[Image:rga8.6.png|center| | [[Image:rga8.6.png|center|450px]] | ||
</li> | </li> | ||
</ol> | </ol> |
Latest revision as of 21:17, 18 September 2023
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This example appears in the Reliability growth reference.
For the data given in the Reliability Data - Logistic Model example, calculate the 2-sided 90% confidence bounds under the Logistic model for the following:
- The parameters [math]\displaystyle{ b\,\! }[/math] and [math]\displaystyle{ k\,\! }[/math].
- Reliability at month 5.
Solution
- The values of [math]\displaystyle{ \hat{b}\,\! }[/math] and [math]\displaystyle{ \hat{k}\,\! }[/math] that were estimated from the least squares analysis in the reliability data example are:
- [math]\displaystyle{ \begin{align} \widehat{b}= & 3.3991 \\ \widehat{\alpha }= & 0.7398 \end{align}\,\! }[/math]
- [math]\displaystyle{ \begin{align} {{b}_{lower}}= & 2.5547 \\ {{b}_{upper}}= & 4.5225 \end{align}\,\! }[/math]
- [math]\displaystyle{ \begin{align} {{k}_{lower}}= & 0.6798 \\ {{k}_{upper}}= & 0.7997 \end{align}\,\! }[/math]
- First, calculate the reliability estimation at month 5:
- [math]\displaystyle{ \begin{align} {{R}_{5}}= & \frac{1}{1+b{{e}^{-5k}}} \\ = & 0.9224 \end{align}\,\! }[/math]
- [math]\displaystyle{ \begin{align} {{[{{R}_{5}}]}_{lower}}= & 0.8493 \\ {{[{{R}_{5}}]}_{upper}}= & 0.9955 \end{align}\,\! }[/math]