Template:Tires: Difference between revisions
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==== BlockSim Solution ==== | ==== BlockSim Solution ==== | ||
To model this system, six diagrams are created: Car, Tire_1, Tire_2, Tire_3, Tire_4 and Spare. Car is the main diagram. In the Car diagram, five subdiagram blocks Tire_1, Tire_2, Tire_3, Tire_4 and Spare are pointed to other four diagrams with the same names. | To model this system, six diagrams are created: Car, Tire_1, Tire_2, Tire_3, Tire_4 and Spare. Car is the main diagram. In the Car diagram, five subdiagram blocks Tire_1, Tire_2, Tire_3, Tire_4 and Spare are pointed to other four diagrams with the same names. For diagram Tire_1, there are two blocks in series. Block Wear 1 represents Wear failure mode and Puncture 1 represents Puncture mode for tire 1 respectively. | ||
Other four diagrams follow the same logic. | |||
Revision as of 17:25, 20 July 2011
Tire Example
Description
A car has four regular tires and a spare tire. Each tire has two failure modes: Wear with Weibull distribution (Beta=2,Eta=40000 miles) and Puncture with Exponential distribution (Mean=1year). Assume that 2 miles=1 hour. Both Wear and Puncture failures are repaired in two days. However, Wear is repaired as good as new, Puncture is repaired as bad as old. When regular tires fail, the spare tire is activated; upon regular tire is restored, the spare tire is deactivated ans put back.
BlockSim Solution
To model this system, six diagrams are created: Car, Tire_1, Tire_2, Tire_3, Tire_4 and Spare. Car is the main diagram. In the Car diagram, five subdiagram blocks Tire_1, Tire_2, Tire_3, Tire_4 and Spare are pointed to other four diagrams with the same names. For diagram Tire_1, there are two blocks in series. Block Wear 1 represents Wear failure mode and Puncture 1 represents Puncture mode for tire 1 respectively.
Other four diagrams follow the same logic.
