Inverse Power Law Example: Difference between revisions
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[ | <noinclude>{{Banner ALTA Examples}} | ||
''This example appears in the [https://help.reliasoft.com/reference/accelerated_life_testing_data_analysis Accelerated life testing reference].'' | |||
< | |||
</noinclude> | |||
Consider the following times-to-failure data at two different stress levels. | Consider the following times-to-failure data at two different stress levels. | ||
[[Image:chp8ex1table.png|center|300px|''Pdf'' of the lognormal distribution with different log-std values.]] | |||
[[Image:chp8ex1table.png|center| | |||
The data set was analyzed jointly in an ALTA standard folio using the IPL-Weibull model, with a complete MLE solution over the entire data set. The analysis yields: | |||
The data set was analyzed jointly | |||
::<math>\widehat{\beta }=2.616464\,\!</math> | |||
::<math>\widehat{\beta }=2.616464</math> | |||
::<math>\widehat{K}=0.001022\,\!</math> | |||
::<math>\widehat{K}=0.001022</math> | |||
::<math>\widehat{n}=1.327292\,\!</math> | |||
::<math>\widehat{n}=1.327292</math> |
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This example appears in the Accelerated life testing reference.
Consider the following times-to-failure data at two different stress levels.
The data set was analyzed jointly in an ALTA standard folio using the IPL-Weibull model, with a complete MLE solution over the entire data set. The analysis yields:
- [math]\displaystyle{ \widehat{\beta }=2.616464\,\! }[/math]
- [math]\displaystyle{ \widehat{K}=0.001022\,\! }[/math]
- [math]\displaystyle{ \widehat{n}=1.327292\,\! }[/math]