Rayleigh Distribution with MLE Solution: Difference between revisions
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Kate Racaza (talk | contribs) (Created page with '{{Reference Example}} This example compares the results for a Rayleigh distribution (1P-Weibull with beta = 2). {{Reference_Example_Heading1}} The data set is from Example 5.…') |
Kate Racaza (talk | contribs) No edit summary |
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{{Reference_Example_Heading3}} | {{Reference_Example_Heading3}} | ||
* The model parameter <math>\hat{\lambda} = \left (\frac{2}{\hat{\eta}} \right)^{2} = 9.12289\times 10^{-4}\,\!</math> | * The model parameter is <math>\hat{\lambda} = \left (\frac{2}{\hat{\eta}} \right)^{2} = 9.12289\times 10^{-4}\,\!</math> | ||
* The Mean Life is 41.49 | * The Mean Life is 41.49 | ||
* The Standard Deviation is 21.70 | * The Standard Deviation is 21.70 | ||
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{{Reference_Example_Heading4}} | {{Reference_Example_Heading4}} | ||
* The model parameter | * The model parameter is: | ||
::<math>\hat{\lambda} = \left (\frac{2}{\hat{\eta}} \right)^{2} = \left (\frac{2}{46.821851} \right)^{2} = 9.12289\times 10^{-4}\,\!</math> | ::<math>\hat{\lambda} = \left (\frac{2}{\hat{\eta}} \right)^{2} = \left (\frac{2}{46.821851} \right)^{2} = 9.12289\times 10^{-4}\,\!</math> | ||
Revision as of 16:39, 9 June 2014
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