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| '''Median Rank Plot Example'''
| | #REDIRECT [[Weibull Distribution Examples]] |
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| In this example, we will determine the median rank value used for plotting the sixth failure from a sample size of ten. This will be used to illustrate two of the built-in functions in Weibull++'s Quick Statistical Reference.
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| '''Solution'''
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| First, open the Quick Statistical Reference and select the '''Inverse F-Distribution Values''' option.
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| In this example, N = 10, j = 6, m = 2(10 - 6 + 1) = 10, and n = 2 x 6 = 12.
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| Thus, from the F-distribution rank equation:
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| ::<math>MR=\frac{1}{1+\left( \frac{10-6+1}{6} \right){{F}_{0.5;10;12}}}</math>
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| Calculate the value of F0.50:10:12 by using the Inverse F-Distribution Values option from the '''Quick Statistical Reference''', or F0.50;10;12 = 0.9886 as shown next:
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| [[Image: F Inverse.png|center|550px]]
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| Consequently:
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| ::<math>MR=\frac{1}{1+\left( \frac{5}{6} \right)\times 0.9886}=0.5483=54.83%</math>
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| Another method is to use the Median Ranks option directly, which yields MR(%) = 54.8305%, as shown next:
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| [[Image: MR.png|center|550px]]
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