|
|
| (5 intermediate revisions by 2 users not shown) |
| Line 1: |
Line 1: |
| '''Median Rank Plot Example'''
| | #REDIRECT [[Weibull Distribution Examples]] |
| | |
| In this example, we will determine the median rank value used for plotting the sixth failure from a sample size of ten. This will be used to illustrate two of the built-in functions in Weibull++'s '''Quick Statistical Reference'''.
| |
| | |
| | |
| '''Solution'''
| |
| | |
| First, open the Quick Statistical Reference by clicking its icon.
| |
| | |
| [[Image: QSP.png|center]] | |
| | |
| or by selecting '''Quick Statistical Reference''' from the '''Home''' menu.
| |
| | |
| In this example N = 10, j = 6, m = 2(10 - 6 + 1) = 10, and n = 2 x 6 = 12.
| |
| | |
| Thus, from the F-distribution rank equation:
| |
| | |
| <center><math>MR=\frac{1}{1+\left( \frac{10-6+1}{6} \right){{F}_{0.5;10;12}}}</math>
| |
| </center>
| |
| | |
| Calculate the value of F0.50:10:12 by using the Inverse F-Distribution Values option from the '''Quick Statistical Reference''', or F0.50;10;12 = 0.9886 as shown next:
| |
| | |
| [[Image: F Inverse.png|center|thumb|250px]]
| |
| | |
| Consequently:
| |
| | |
| <center><math>MR=\frac{1}{1+\left( \frac{5}{6} \right)\times 0.9886}=0.5483=54.83%</math>
| |
| </center>
| |
| | |
| Another method is to use the Median Ranks option directly, which yields MR(%) = 54.8305%, as shown next:
| |
| [[Image: MR.png|center|thumb|250px]]
| |